Central Board of Secondary Education (CBSE) has released a notification for the recruitment of Teachers through Central Teacher Eligibility Test (CTET) for Class I to VIII. Interested candidates may check the vacancy details and apply online from 19-08-2019 to 18-09-2019.
More details about CTET 2019, including number of vacancies, eligibility criteria, selection procedure, how to apply and important dates, are given below:
• Post Name: Central Teacher Eligibility Test (CTET)
• No. of Vacancies: To Be Announced
• Pay Scale: Not Mentioned
Job Location: All India
Eligibility Criteria for CBSE – CTET Teacher for Class I to VIII:
For Class I to V (Primary Stage): Candidates should have passed Senior Secondary with minimum 50% marks and 2 year Diploma in Elementary Education OR 4 year Bachelor of Elementary Education (B.El.Ed.) OR 2 year Diploma in Special Education.
For Class VI to VIII (Elementary Stage): Candidates should have passed Graduation Degree and passed or appearing in Bachelor of Education (B.Ed.) (Special Education) OR 2 year Diploma in Elementary Education OR 4 year Bachelor of Elementary Education (B.El.Ed.).
Age Limit: To Be Announced
Selection Process: Selection of candidates will be made on the basis of Preliminary and Main Examination.
Application Fee: All candidates have to pay application fee through online mode using Net-banking/Credit or Debit Card/E-Challan.
For One Paper For Both Papers
General/UR/OBC Rs. 700 Rs. 1,200
SC/ST/PH Rs. 350 Rs. 600
How to Apply: Interested and eligible candidates may apply online through CTET website – https://ctet.nic.in/ – from 19-08-2019 to 18-09-2019.
• Starting Date of Online Application:19-08-2019
• Last Date of Online Application:18-09-2019
• Last Date for Submitting Application Fee:23-09-2019
• Date of Examination:08-12-2019
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