**Quantitative**

Aptitude Study Notes for Bank & SSC Exam

Aptitude Study Notes for Bank & SSC Exam

**CALCULATE AVERAGE SHORTCUT TRICKS**

You know that quantitative

aptitude section is most important in

other competitive exams because if you want good score in bank exam then you

have to score good in maths. In competitive exams the most important thing is

time management, if you know how to manage your time then you can do well in

tricks and formula are comes into action. So continuously we are providing

shortcut tricks on different maths topics.

aptitude section is most important in

**bank**

exams in PO andexams in PO and

**Clerk**and forother competitive exams because if you want good score in bank exam then you

have to score good in maths. In competitive exams the most important thing is

time management, if you know how to manage your time then you can do well in

**Bank Exams.**That’s where maths shortcuttricks and formula are comes into action. So continuously we are providing

shortcut tricks on different maths topics.

The one of the most important

topic in maths is average. You should know how to

providing shortcut tricks to calculate average in maths.

topic in maths is average. You should know how to

**calculate Average**in very short time. For this here we areproviding shortcut tricks to calculate average in maths.

**AVERAGE**

An average, or more accurately an

arithmetic mean is, in crude terms, the sum of n different data divided by n.

arithmetic mean is, in crude terms, the sum of n different data divided by n.

**HOW TO CALCULATE AVERAGE:**

For example, if a batsman scores

30, 50 and 25 runs in first, second and third innings respectively, then his

average runs in 3 innings is equal to

30, 50 and 25 runs in first, second and third innings respectively, then his

average runs in 3 innings is equal to

30+50+25/3; =39 runs

**Therefore, the two mostly used formulas in this chapter**

are:

are:

Average= total of data/no. of

data

data

And total = average × no. of data

**Important**

Formulae Related to Calculate Average of numbers:

Formulae Related to Calculate Average of numbers:

1.

Average of first n natural number = (n+1)/2

Average of first n natural number = (n+1)/2

3.

Average of first n odd number = n

Average of first n odd number = n

4.

Average of consecutive number = (First number +Last number)/2

Average of consecutive number = (First number +Last number)/2

5.

Average of 1 to n odd numbers = (Last odd number+1)/2

Average of 1 to n odd numbers = (Last odd number+1)/2

6.

Average of 1 to n even numbers = (Last even number+2)/2

Average of 1 to n even numbers = (Last even number+2)/2

7.

Average of squares of first n natural numbers = [(n+1) (2n+1)]/6

Average of squares of first n natural numbers = [(n+1) (2n+1)]/6

8.

Average of the cubes of first n natural number = [n (n+1) ^2]/4

Average of the cubes of first n natural number = [n (n+1) ^2]/4

9.

Average of n multiples of any number = [Number*(n+1)]/2

Average of n multiples of any number = [Number*(n+1)]/2

**Examples**

with shortcut tricks on how to calculate Average are given below:

with shortcut tricks on how to calculate Average are given below:

**Ex: the**

average age of 30 boys of a class is equal to 14 yrs. When the age of the class

teacher is included the average becomes 15 yrs. Find the age of class teacher?

average age of 30 boys of a class is equal to 14 yrs. When the age of the class

teacher is included the average becomes 15 yrs. Find the age of class teacher?

**Solution:**total ages of 30 boys = 14 × 30

= 420yrs.

Total ages when class teacher is

included = 15 × 31 = 465yrs.

included = 15 × 31 = 465yrs.

So age of class teacher = 465 –

420 = 45 yrs.

420 = 45 yrs.

**Shortcut trick:**age of new entrant = new average

+ no. of old members × Increase in average = 15 + 30 (15-14) = 45 yrs.

**Ex: the**

average weight of 4 men is increased by 3 kg when one of them who weigh 120kg

is replaced by another man. What is weight of the new man?

average weight of 4 men is increased by 3 kg when one of them who weigh 120kg

is replaced by another man. What is weight of the new man?

**Solution:**

**by shortcut trick:**if the average is increased by 3 kg, then the

sum of weight increases by 3 × 4 = 12 kg.

And this increase in weight is

due to the extra weight included due to the inclusion of new person.

due to the extra weight included due to the inclusion of new person.

So weight of new man = 120 + 12 =

132 kg.

132 kg.

We can also solve this question

by Direct formula: weight of new person = weight of removed person+ no. of

persons × increase in average = 120 + 4 * 3= 132 kg.

by Direct formula: weight of new person = weight of removed person+ no. of

persons × increase in average = 120 + 4 * 3= 132 kg.

**Ex: the**

average of marks obtained by 120 candidates in a certain examination is 35. If the

average marks of passed the examination?

average of marks obtained by 120 candidates in a certain examination is 35. If the

average marks of passed the examination?

**Solution:**Let the number of passed

candidates be x.

Then total marks = 120 × 35 = 39x

+ (120-x) * 15

+ (120-x) * 15

Or, 4200 = 39x + 1800 – 15x

Or, 24x = 2400

X = 100

So number of passed candidates =

100.

100.

**We can also**

solve this question by shortcut trick direct formula:

solve this question by shortcut trick direct formula:

Number of passed candidates =

total candidates ( total average –

failed average) / passed average-failed average

failed average) / passed average-failed average

And number of failed candidates=

Total candidates (passed average –

total average) / passed average – failed average

total average) / passed average – failed average

by this, we can solve number of

passed candidates = 120 (35 – 15) / 39 – 15

passed candidates = 120 (35 – 15) / 39 – 15

= 100

**Ex: A**

batsman in his 17

his average by 3. What is his average after 17 innings?

batsman in his 17

^{th}innings makes a score of 85, and thereby increaseshis average by 3. What is his average after 17 innings?

**Solution:**let the average after 16

^{th}

innings be x, then 16x + 85

= 17 (x + 3) = Total score after

17

17

^{th}innings.
X = 85 – 51 = 34

Average after 17 innings = x + 3

= 34 + 3 = 37

= 34 + 3 = 37

**Shortcut tricks**

or direct formula:

or direct formula:

Average after 16 innings = 85 – 3

* 17 = 34

* 17 = 34

Average after 17 innings = 85 – 3

(17 – 1) = 37.

(17 – 1) = 37.

**Ex: a**

cricketer has completed 10 innings and his average is 21.5 runs. How many runs

must he make in his next innings so as to raise his average to 24?

cricketer has completed 10 innings and his average is 21.5 runs. How many runs

must he make in his next innings so as to raise his average to 24?

**Solution:**total of 10 innings = 21.5 × 10

= 215

Suppose he needs a score of x in

11

11

^{th}innings; then average in 11 innings = 215 + x / 11 =24
Or x, = 264 – 215 = 49

**Shortcut tricks**

or direct formula:

or direct formula:

Required score = 11 × 24 – 21.5 ×

10 = 49

10 = 49

Note: the above formula is based

on the theory that the difference is counted due to the score in last innings.

on the theory that the difference is counted due to the score in last innings.

**Ex: in a**

class there are 20 boys whose average age is decreased by 2 months, when one

boy aged 18 years is replaced by a new boy. Find the age of the new boy.

class there are 20 boys whose average age is decreased by 2 months, when one

boy aged 18 years is replaced by a new boy. Find the age of the new boy.

**Solution: Shortcut**

trick:

trick:

Age of new person = age of

removed person – no. of persons × decrease in average age

removed person – no. of persons × decrease in average age

= 18 – 20 × 2/12

= 18 – 10/3

= 44/3

= 14 yrs 8 months.

**Also**

read maths study notes & shortcut tricks on these topics:

read maths study notes & shortcut tricks on these topics:

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