**AGE PROBLEMS WITH SOLUTIONS**QUANTITATIVE APTITUDE STUDY NOTES FOR BANK AND SSC EXAM

You know that quantitative

aptitude section is most important in

other competitive exams because if you want good score in bank exam then you

have to score good in maths. In competitive exams the most important thing is

time management, if you know how to manage your time then you can do well in

tricks and formula are comes into action. So continuously we are providing

shortcut tricks on different maths topics.

aptitude section is most important in

**bank**

exams in PO andexams in PO and

**Clerk**and forother competitive exams because if you want good score in bank exam then you

have to score good in maths. In competitive exams the most important thing is

time management, if you know how to manage your time then you can do well in

**Bank Exams.**That’s where maths shortcuttricks and formula are comes into action. So continuously we are providing

shortcut tricks on different maths topics.

Today’s topic is

most important topic in quantitative aptitude section in bank and ssc exam. You

should know how to calculate Age problems questions and answers in very short

time for bank exam. From this chapter around 1-2 questions are given in the

are providing

quicker method to calculate quantitative apptitude questions in very short time.

**AGE PROBLEMS.**This is the one of themost important topic in quantitative aptitude section in bank and ssc exam. You

should know how to calculate Age problems questions and answers in very short

time for bank exam. From this chapter around 1-2 questions are given in the

**SBI and IBPS exams.**For this here weare providing

**maths shortcut tricks**andquicker method to calculate quantitative apptitude questions in very short time.

To solve the problems based on

ages, students require the knowledge of linear equations. This method needs

some basic concepts as well as some more time than it deserves. Sometimes it is

easier to solve the problems by taking the given choices in account. But this

hit-and-trial method proves costly sometimes, when we reach our solution much

later. We have tried to evaluate some easier as well as quicker methods to

solve this type of questions on

section, our attempt is to minimise your difficulties.

ages, students require the knowledge of linear equations. This method needs

some basic concepts as well as some more time than it deserves. Sometimes it is

easier to solve the problems by taking the given choices in account. But this

hit-and-trial method proves costly sometimes, when we reach our solution much

later. We have tried to evaluate some easier as well as quicker methods to

solve this type of questions on

**.**Although, we are not able to cover each type of questions in thissection, our attempt is to minimise your difficulties.

**Have a look at the following questions on****age problems:****Ex. 1:**The age of the father 3 years

ago was 7 times the age of his son. At present, the father’s age is five times

that of his son. What are the present ages of the father and the son?

**Ex. 2:**At present, the age of the

father is five times the age of his son. Three years hence, the father’s age

would be four times that of his son. Find the present ages of the father and

the son.

**Ex. 3:**Three years earlier, the father was

7 times as old as his son. Three years hence, the father’s age would be four

times that of his son. What are the present ages of the father and the son?

**Age**

problems solutions by the conventional method:

problems solutions by the conventional method:

**Solution 1:**let the present age of son = x

yrs

Then, the present age of father =

5x yrs

5x yrs

3 years ago,

7 (x – 3) = 5x – 3

Or, 7x – 21 = 5x – 3

Or, 2x = 18

Or, x = 9

Therefore, son’s age = 9 yrs

Father’s age = 45 yrs

**Solution 2:**let the present age of son = x

yrs

Then, the present age of son = x

yrs

yrs

Then, the present age of father =

5 yrs

5 yrs

3 yrs hence,

4(x + 3) = 5x + 3

Or, x + 12 = 5x + 3

X = 9 yrs. Therefore, son’s age =

9 yrs

9 yrs

And father’s age = 45 yrs

**Solution 3:**let the present age of son = x

yrs

And the present age of father = y

yrs

yrs

3 yrs earlier, 7 (x – 3) = y – 3

Or, 7x – y = 18 ……….. (1)

3 yrs hence, 4 (x + 3) = y + 3

Or, 4x + 12 = y + 3

Solving (1) & (2) we get, x =

9 yrs & y = 45 yrs

9 yrs & y = 45 yrs

by maths shortcut trick:

Solution: son’s age = 3*(7-1) /

7-5

7-5

= 9 yrs

And father’s age = 9*5 = 45 yrs.

Undoubtedly you get confused with

the about method, but it is very easy to understand and remember. see the

following form of question:

the about method, but it is very easy to understand and remember. see the

following form of question:

short tricks and quicker method:**Age Problems**Mathsshort tricks and quicker method:

**Q: t1 yrs earlier the father’s age was x times that of**

his son. At present, the father’s age is y times that of his son. What are the

present ages of the son and the father?

his son. At present, the father’s age is y times that of his son. What are the

present ages of the son and the father?

Solution: son’s age = (4-1)*3 /

5-4

5-4

= 9 yrs

And father’s age = 9*5 = 45 yrs.

**Q: The present age of the father is y times the age of**

his son. t2 yrs hence, the father’s age become z times the age of his son. What

are the present ages of the father and his son?

his son. t2 yrs hence, the father’s age become z times the age of his son. What

are the present ages of the father and his son?

Solution:

3(4-1) + 3(7-1) / 7-4

3(4-1) + 3(7-1) / 7-4

=

9+18 / 3

9+18 / 3

=

9 yrs

9 yrs

**Q: t1 yrs earlier the age of the father was x time the**

age of his son t2 yrs hence, the age the father becomes z times the age of his

son. what are the present ages of the son and the father?

age of his son t2 yrs hence, the age the father becomes z times the age of his

son. what are the present ages of the son and the father?

**Some other examples on age problems with solutions:**

**Ex:**Ten years ago, A was half of B

in age. If the ratio of their present age is 3 : 4, what will be the total of

their present ages?

**Solution:**10 yrs ago, A was ½ of B’s age.

At present, A is ¾ of B’s age.

B’s age

use formula (1)

10 ( ½ – 1) / ½ – ¾

= 20 yrs

A’s age = ¾ of 20 = 15 yrs

**Ex:**After 5 yrs, the age of a father

will be thrice the age of his son, whereas five years ago, he was 7 times as old

as his son was. What are their present ages?

**Solution:**formula (3) will be used in this

case. So

Son’s age = 5(7-1)+5(3-1) / 7-3

= 10 yrs

From the first relationship of

ages, if F is the age of the father then

ages, if F is the age of the father then

F + 5 = 3(10 + 5)

F = 40 yrs.

**Ex:**10 yrs ago, Sita’s mother was 4

times older than her daughter. After 10 yrs, the mother will be two times older

than the daughter. What is the present age of Sita?

**Solution:**In this case also, formula (3)

will be used.

Daughter’s age = 10(4-1) +

10(2-1) / 4-2

10(2-1) / 4-2

= 20 yrs

**To**

view quantitative aptitude study notes on other topics CLICK HERE

view quantitative aptitude study notes on other topics CLICK HERE