**Quantitative Aptitude Study Notes for Bank Exams PO and**

Clerk

Clerk

**RATIO AND PROPORTION SHORTCUT TRICKS**

You know that quantitative

aptitude portion is most important in

other competitive exams because if you want a good score in bank exam then you

have to score good in maths.

quantitative aptitude section in

competitive exams the most important thing is time management, if you know how to manage

your time then you can do well in

Maths shortcut tricks and formula are comes into action. Examples on All shortcut

tricks on

better understand

aptitude portion is most important in

**bank PO and****Clerk Exams**and forother competitive exams because if you want a good score in bank exam then you

have to score good in maths.

**Ratio and**

proportion shortcut tricksquestions are very important questions forproportion shortcut tricks

quantitative aptitude section in

**Bank**

Examsfor SBI, IBPS, RRB PO and CLERK exams and other competitive exams. InExams

competitive exams the most important thing is time management, if you know how to manage

your time then you can do well in

**Bank**

Exams. That’s whereExams

Maths shortcut tricks and formula are comes into action. Examples on All shortcut

tricks on

**RATIO AND PROPORTION for bank**

examsare provided below in this page. These examples will help you toexams

better understand

**shortcut tricks on**

ratio andratio and

**proportion.****RATIO:**

The number of times one quantity

contains another quantity of the same kind is called the ratio of the two

quantities or Ratio is a quantity which represents the relationship between two

similar quantities.

contains another quantity of the same kind is called the ratio of the two

quantities or Ratio is a quantity which represents the relationship between two

similar quantities.

For example the ratio 4 to 5 is

written as 4:5 or 4/5. 4 and 5 are called the terms of the ratio. 4 is the

first term and 5 is the second term.

written as 4:5 or 4/5. 4 and 5 are called the terms of the ratio. 4 is the

first term and 5 is the second term.

Here first term or numerator i.e.

4 is called the ANTECEDENT and second term or denominator i.e. 5 is called the

CONSEQUENT.

4 is called the ANTECEDENT and second term or denominator i.e. 5 is called the

CONSEQUENT.

**PROPORTION:**

Consider the two ratios:

**1**

^{st}Ratio**4:12**

**2**

^{nd}Ratio**7:21**

From the first ratio 4 is the

one-third of 12, and form the second ratio 7 is the one-third of 21. By this

both the ratios are equal. So the equality of ratios is called PROPORTION.

one-third of 12, and form the second ratio 7 is the one-third of 21. By this

both the ratios are equal. So the equality of ratios is called PROPORTION.

The 4, 12, 7 and 21 are said to

be in proportion.

be in proportion.

The proportion may be written as

**4 : 12 : : 7 : 21**

**Or**

**4:12=7:21**

**Or**

**4/12=7/21**

The numbers 4, 12, 7 and 21 are

called the terms, 4 is the first term, 12 is the second term, 7 is the third

term and 21 is the fourth term.

called the terms, 4 is the first term, 12 is the second term, 7 is the third

term and 21 is the fourth term.

First and fourth terms are called

the extremes terms, and the second and third terms are called as mean terms.

the extremes terms, and the second and third terms are called as mean terms.

**Check Our Video Lecture Also: Ratio Tricks**

**Examples**

with shortcut tricks on ratio and proportion are given below:

with shortcut tricks on ratio and proportion are given below:

**Find the**

__Ex for compound ratio:__ration compounded of the four ratios:

2:3, 4:5, 8:21, 7:10

**the required ratio = 2×4×8×7/3×5×21×10;**

__Solution:__32/225

Inverse ratio:

If 9:7 be the given ration, then

1/9:1/7 or 7:9 is called its inverse or reciprocal ratio.

1/9:1/7 or 7:9 is called its inverse or reciprocal ratio.

**Ex: divide**

1562 into two parts such that one may be to the other as 5:6.

1562 into two parts such that one may be to the other as 5:6.

**Solution:**

1

^{st}part = 5×1562/5+6
=5×1562/11

=700

2

^{nd}part = 6×1562/11
= 852.

**Ex: A, B, C**

and D are four quantities of the same kind such that

and D are four quantities of the same kind such that

**A:B=3:4, B_C=8:9,**

C_D=15:16

C_D=15:16

a)

Find the ratio A:D

Find the ratio A:D

b)

Find A:B:C

Find A:B:C

**Solution:**

a)

A/B=3:4, B/C=8:9, C/D=15:16

A/B=3:4, B/C=8:9, C/D=15:16

Then; A/D= A/B × B/C × C/D

= 3/4 × 8/9 × 15/16

= 7:30

b)

A:B=3:4 = 3*2:4*2; Now A:B becomes 6:8, the value of B becomes

equal in both the ratios, in ratio A:B and B:C i.e. 6.

A:B=3:4 = 3*2:4*2; Now A:B becomes 6:8, the value of B becomes

equal in both the ratios, in ratio A:B and B:C i.e. 6.

By this the ratio A:B:C will be

6:8:9

6:8:9

**Ex: the**

ratio of the money with Anu and Sheetal is 7:15 and that with Sheetal and

Poonam is 7:16. If Anu has 490 Rs. Then how much money does Poonam have?

ratio of the money with Anu and Sheetal is 7:15 and that with Sheetal and

Poonam is 7:16. If Anu has 490 Rs. Then how much money does Poonam have?

**Solution:**Anu:Sheetal:Poonam;

7 : 15

7 :

16

16

49: 105 : 240

The ratio of money with

Anu:Sheetal:Poonam is 49: 105 :

240

Anu:Sheetal:Poonam is 49: 105 :

240

So Poonam have Rs. 2400.

**Ex: one man**

adds 3 litres of water to 12 liters of milk and another 4 liters of water to 10

liters of milk. What is the ratio of the strengths of milk in the two mixtures?

adds 3 litres of water to 12 liters of milk and another 4 liters of water to 10

liters of milk. What is the ratio of the strengths of milk in the two mixtures?

**Solution:**Strength of milk in the first

mixture = 12/12+3=12/15

Strength of milk in the second

mixture = 10/10+4 = 10/14

mixture = 10/10+4 = 10/14

Then the ratio of strengths =

12/15 : 10/14

12/15 : 10/14

=12*14 : 15*10 = 28:25

**Ex: find the**

fourth proportional to the numbers 7, 21 and 3.

fourth proportional to the numbers 7, 21 and 3.

**Solution:**if x be the fourth proportional,

then 7_21=3:x

X=21×3 / 7;

= 9

**Ex: if 8 men**

can reap 80 hectares in 24 days, how many hectares can 36 men reap in 30 days?

can reap 80 hectares in 24 days, how many hectares can 36 men reap in 30 days?

**Solution:**1

^{st}: if 8 men can

reap 80 hectares, then 36 men reap in

8 M : 36 M = 80 hectares : x no

of hectares

of hectares

X = 36×80 / 8 =360 hectares

2

can be reaped in 24 days, then hectares reaped in 30 days is

^{nd}: if 360 hectarescan be reaped in 24 days, then hectares reaped in 30 days is

24 days : 30 days = 360 hectares

: x no. of hectares

: x no. of hectares

X= 30×360 / 24

= 450.

**Ex: divide**

Rs 1350 into three shares proportional to the numbers 2, 3 and 4.

Rs 1350 into three shares proportional to the numbers 2, 3 and 4.

**Solution:**1

^{st}share = Rs 1350 ×

2 /2+3+4

= 1350 × 2/9; = Rs 300

2

1350×3/9 = Rs 450

^{nd}share = Rs1350×3/9 = Rs 450

3

4/9 =Rs 600

^{rd}share = Rs 1350 ×4/9 =Rs 600