**Time and Work Problems For Bank Exam**

**Quantitative Aptitude Study Notes for Bank Exam**

You know that quantitative

aptitude section is most important in

good score in bank exam then you have to score good in maths. In competitive

exams the most important thing is time management, if you know how to manage

your time then you can do well in

comes into action. So continuously we are providing shortcut tricks on

different maths topics. Today’s topic is

quantitative aptitude section in bank and SSC exam. You should know how to solve

short time for

chapter around 1-2 questions are given in the

time. Before going to solve questions for time and work, we study little bit

about basics and formulas for time and work. If ‘M

work in ‘D

work in ‘D

relationship of

relationship can be taken as a very basic and all-in-one formula. We also

derive:

aptitude section is most important in

**bank**

examsin PO and Clerk and for other competitive exams because if you wantexams

good score in bank exam then you have to score good in maths. In competitive

exams the most important thing is time management, if you know how to manage

your time then you can do well in

**Bank**

Examsas well as in other competitive exams. That’s whereExams

**maths shortcut tricks and formula are**comes into action. So continuously we are providing shortcut tricks on

different maths topics. Today’s topic is

**time and work problems for bank exam.**This is the one of the most important topic inquantitative aptitude section in bank and SSC exam. You should know how to solve

**time and work questions**in veryshort time for

**bank exam.**From thischapter around 1-2 questions are given in the

**SBI and IBPS exams.**For this here we are providing**shortcut tricks**and quicker method to solve**time and work problems**in very shorttime. Before going to solve questions for time and work, we study little bit

about basics and formulas for time and work. If ‘M

_{1}’ persons can do ‘W_{1}’work in ‘D

_{1}’ days and ‘M_{2}’ persons can do ‘W_{2}’work in ‘D

_{2}’ days then we have a very special general formula in therelationship of

**M1**

D1 W2 = M2 D2 W1. The aboveD1 W2 = M2 D2 W1

relationship can be taken as a very basic and all-in-one formula. We also

derive:

1.

More men less days and conversely more days less men.

More men less days and conversely more days less men.

2.

More men more work and conversely more work more men.

More men more work and conversely more work more men.

3.

More days more work and conversely more work more days.

More days more work and conversely more work more days.

If we include the working hours

(say T1 and T2) for the two groups then the relationship is

(say T1 and T2) for the two groups then the relationship is

**M1**

D1 T1 W2 = M2 D2 T2 W1.

D1 T1 W2 = M2 D2 T2 W1.

Again, if the efficiency (say E1

and E2) of the persons in two groups is different than the relationship is

and E2) of the persons in two groups is different than the relationship is

**M1**

D1 T1 E1 W2 = M2 D2 T2 E2 W1.

D1 T1 E1 W2 = M2 D2 T2 E2 W1.

**Time and work questions with answers:**

Now, we should go ahead starting

with simpler to difficult and more difficult questions.

with simpler to difficult and more difficult questions.

**Ex. 1: ‘A’ can do a piece of work in 5 days. How many**

days will he take to complete 3 works of same type?

days will he take to complete 3 works of same type?

**Solution:**

we recall the statement: “ More

work more days” It simply means’ that we will get the answer by multiplication.

work more days” It simply means’ that we will get the answer by multiplication.

Thus, our answer = 5*3 = 15 days.

This way of solving the question is very simple,

but you should know how the “basic formula” could be used in this question.

but you should know how the “basic formula” could be used in this question.

Recall the basic formula: M1 D1

W2 = M2 D2 W1.

W2 = M2 D2 W1.

As ‘A’ is the only persn to do

the work in both the cases, so

the work in both the cases, so

M1 = M2 = 1 (useless to carry it)

D1 = 5 days, W1 = 1, D2 = ? and

W2 = 3

W2 = 3

Putting the values in the formula

we have,

we have,

5 * 3 = D1 * 1

Or, D2 = 15 days.

**Ex. 2: 16 men can do a piece of work in 10 days, how many**

men ae needed to complete the work in 40 days?

men ae needed to complete the work in 40 days?

**Solution:**

To do a work in 10 days, 16 men

are needed.

are needed.

Or, to do the work in 1 day, 16 *

10 men are needed.

10 men are needed.

So, to do the work in 40 days,

16*10 / 40 = 4 men are needed.

16*10 / 40 = 4 men are needed.

This was the method used for

non-objective exams.

non-objective exams.

We should see how the ‘basic

formula’ works here.

formula’ works here.

M1 = 16, D1 = 10, W1 = 1

And

M2 = 7, D2 = 40, W2 = 1

Thus, form M1 D1 W2 = M2 D2 W1.

16 * 10 = M2 * 40

Or, M2 = 16*10 / 40 = 4 men

By rule of fractions: to do the

work in 40 days we need less number of men than 10. So we should multiply 10 with a fraction

which is less than 1. And that fraction is 10/40. Therefore, required number of

men

work in 40 days we need less number of men than 10. So we should multiply 10 with a fraction

which is less than 1. And that fraction is 10/40. Therefore, required number of

men

= 16 * 10 / 40 = 4

**Ex. 3: A can do a piece of work in 5 days, and B can do**

it in 6 days. How long will they take if both work together?

it in 6 days. How long will they take if both work together?

**Solution:**

‘A’ can do 1/5 work in 1 day.

‘B’ can do 1/6 work in 1 day.

Thus, ‘A’ and ‘B’ can do (1/5 +

1/6) work in 1 day.

1/6) work in 1 day.

‘A’ and ‘B’ can do the work in 1/

1/5+1/6 days = 30/11 = 2

1/5+1/6 days = 30/11 = 2

^{8}/_{11 }days
By the Theorem: A + B can do the

work in 5*6 / 5+6 days = 30/11 = 2

work in 5*6 / 5+6 days = 30/11 = 2

^{8}/_{11 }days**Theorem:**if A, B and C can do a work in x, y and z

days respectively then all of them working together can finish the work in xyz

/ xy +yz + xz days.

**Ex. 4: In the above question, if C who can do the work in**

12 days, joins them, how long will they take to complete the work?

12 days, joins them, how long will they take to complete the work?

**Solution:**by the theorem: ‘A’, ‘B’ and ‘C’ can do the

work in

5 * 6 * 12 / 5*6 +6*12 + 5*12

= 360/162

= 2

^{2}/_{9 }days**Theorem and shortcut trick for time and work question:**if A and B together can do a

piece of work in x das and A alone can do it in y days. Then B alone can do the

work in xy / x-y days.

**Ex. 5: A and B together can do a piece of work in 6 days**

and A alone can do it in 9 days. In how many days can B alone do it?

and A alone can do it in 9 days. In how many days can B alone do it?

**Solution:**

A and B can do 1/6

of the work in 1 day.

^{th}of the work in 1 day.

A alone can do 1/9

of the work in 1 day.

^{th}of the work in 1 day.

B alone can do the whole work in

18 days.

18 days.

**By the theorem or shortcut trick:**

B alone can do the whole work in

= 6*9 / 9-6

54 / 3 = 18 days

**Ex. 6: if 3 men or 4 women can reap a field in 43 days,**

how long will 7 men and 5 women take to reap it?

how long will 7 men and 5 women take to reap it?

**Solution:**

3 men reap 1/43

the field in 1 day.

^{rd}ofthe field in 1 day.

1 men reaps 1 / 43*3 rd of the field in 1 day.

4 men reap 1/43 rd of the field in 1 day.

1 woman reaps 1 / 43*4 of the field in 1 day.

7 men and 5 women reap (7 / 43*3

+ 5 / 43*4) = 1/12

+ 5 / 43*4) = 1/12

^{th}of the field in 1 day.
7 men and 5 women will reap the

whole field in 12 days.

whole field in 12 days.

**Shortcut method for time and work:**

Required number of days = 1 /

(7/43*3 + 5/43*4)

(7/43*3 + 5/43*4)

43*3*4 / 7*4 + 5*3

= 12 days

**Note:**the above formula is very easy to remember.

If we divide the question in two

arts and call the first part as OR – part and the second part as AND – part then

arts and call the first part as OR – part and the second part as AND – part then

7 / 43*3 = number of men in AND

part / Number of days * Number of men in OR part

part / Number of days * Number of men in OR part

**To**

view quantitative study notes on other topics CLICK HERE

view quantitative study notes on other topics CLICK HERE